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3^4x-5=(1/27)^2x+10
We move all terms to the left:
3^4x-5-((1/27)^2x+10)=0
Domain of the equation: 27)^2x+10)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3^4x-((+1/27)^2x+10)-5=0
We multiply all the terms by the denominator
3^4x*27)^2x+10)-((-5*27)^2x+10)+1=0
We add all the numbers together, and all the variables
3^4x*27)^2x+10)-((-135)^2x+10)+1=0
Wy multiply elements
81x^5-135)^2x+10)+1=0
We do not support expression: x^5
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